I'm on digest, so this was probably already responded to, but: Oh come on,
end the geek parade. Didn't we all figure this sort of thing out watching
Square One when we were little?
Simple algebra:
(10x + y) - (x + y) = 9x
All you have to do, when given the number, is add whatever number would make
the sum of the digits divisible by 9.
Here, prove this instead:
x^n + y^n = z^n has no solutions for n >=3
M.
Brian MacDonald <brianm@kuci.org> wrote:
quoted 20 lines * Think of any number that has at least two digits. (The number cannot be
>* Think of any number that has at least two digits. (The number cannot be
>all zeroes)
>
>* Add up all the digits in that number
>
>* Subtract this total from the original number
>
>* Scratch out one of the digits from this result, as long as it is NOT a
>zero.
>
>* Give me the list of the remaining digits. (If there are no remaining
>digits, you must tell me "there are no remaining digits")
>
>..and..
>
><HEAVY REVERB>
>I WILL TELL YOU WHAT DIGIT YOU SCRATCHED OUT!!!
></HEAVY REVERB>
>
>What is my secret? And why does it work?
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